A comforting Romanian-style chicken dish inspired by a family recipe. Tender, golden chicken pieces are cooked in a rich garlic and chicken broth sauce with onion, bay leaf and rosemary. Perfect served with polenta, mashed potatoes or fresh bread.
Creamy Romanian Chicken in Garlic & Herb Sauce
Ingredients
For the Chicken
For the Sauce
Instructions
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Prepare the flour coating
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Place the flour on a plate.
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Season with salt, black pepper and chicken seasoning.
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Mix well.
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Coat and brown the chicken
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Cut the chicken breast into evenly sized pieces.
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Coat each piece in the seasoned flour, shaking off any excess.
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Heat oil in a large frying pan.
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Fry the chicken for approximately 5–6 minutes, turning until golden on both sides.
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Remove the chicken from the pan and set aside.
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Prepare the garlic and onion
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Add a little more oil to the same pan.
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Add the chopped onion and garlic.
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Pour in about ½ cup of chicken broth and stir well.
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Cook until the onion softens.
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Make the sauce
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Add the remaining chicken broth, bay leaf and rosemary.
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Stir to combine and bring to a gentle simmer.
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Finish cooking
- Return the browned chicken to the pan.
- Simmer gently for about 15 minutes, or until the chicken is fully cooked and the sauce has thickened.
- Remove the bay leaf and rosemary before serving, if desired.
Serve hot with traditional Romanian polenta (mămăligă), mashed potatoes or crusty bread.