Include in Print View:

Creamy Romanian Chicken in Garlic & Herb Sauce

A comforting Romanian-style chicken dish inspired by a family recipe. Tender, golden chicken pieces are cooked in a rich garlic and chicken broth sauce with onion, bay leaf and rosemary. Perfect served with polenta, mashed potatoes or fresh bread.

Ingredients
    For the Chicken
  • Chicken breast, cut into pieces
  • ½ cup plain flour
  • Salt, to taste
  • Black pepper, to taste
  • Chicken seasoning, to taste
  • Oil, for frying
    • For the Sauce
  • 1 medium onion, finely chopped
  • 3-4 garlic cloves, chopped
  • 2 cups chicken broth
  • 1 bay leaf
  • 1 sprig fresh rosemary
  • A little extra oil
Instructions
  1. 1
    Prepare the flour coating

    • Place the flour on a plate.

    • Season with salt, black pepper and chicken seasoning.

    • Mix well.

  2. 2
    Coat and brown the chicken

    • Cut the chicken breast into evenly sized pieces.

    • Coat each piece in the seasoned flour, shaking off any excess.

    • Heat oil in a large frying pan.

    • Fry the chicken for approximately 5–6 minutes, turning until golden on both sides.

    • Remove the chicken from the pan and set aside.

  3. 3
    Prepare the garlic and onion

    • Add a little more oil to the same pan.

    • Add the chopped onion and garlic.

    • Pour in about ½ cup of chicken broth and stir well.

    • Cook until the onion softens.

  4. 4
    Make the sauce

    • Add the remaining chicken broth, bay leaf and rosemary.

    • Stir to combine and bring to a gentle simmer.

  5. 5
    Finish cooking
    • Return the browned chicken to the pan.
    • Simmer gently for about 15 minutes, or until the chicken is fully cooked and the sauce has thickened.
    • Remove the bay leaf and rosemary before serving, if desired.
    Step by step Youtube Video
    Serve hot with traditional Romanian polenta (mămăligă), mashed potatoes or crusty bread.
Read it online: https://yummy.expert/recipe/creamy-romanian-chicken-in-garlic-herb-sauce/